Question

could use some help please, im completely lost

Answer 1

\[18g ^{3}h ^{9} \over 6g ^{6}g ^{5}\]

Answer 2

multiply numbers with powers with the same base = you can add the powers together
ie b^2 times b^7 = b^9

Answer 3

divide numbers with powers with the same base = you can subtract the powers from one another
ie (b^12) / (b^5) = b^(12-5) = b^7

Answer 4

follow so far?

Answer 5

im think so lol

Answer 6

cool, so divvy it up first into manageable pieces
whats 18/6 = ?

Answer 7

its 3

Answer 8

sweet, so replace the 18/6 in the eqn with just a 3

Answer 9

now : bottom line g^6 times g^5 = g^(6+5) =g^??

Answer 10

g will equal g^11??

Answer 11

sweet so your equation now looks something like:

Answer 12

\[\frac{ 3g ^{3}h ^{9} }{ g ^{11} } \]

Answer 13

so tidy some more:
g^3 / g^11 = g^ (3-11) = g^ (??)

Answer 14

g^-8???

Answer 15

yep, and anything to a negative power = 1/ nuber to that power
ie b^-6 = 1/ b^6

Answer 16

so you equation should now look like:
\[\frac{ 3h ^{9} }{ g ^{8} }\]

Answer 17

and that's as reduced as it can get

Answer 18

okay thanks i get better now ( ; lol

Answer 19

there's a great quick reference table here too if you like:
http://www.mathsisfun.com/algebra/exponent-laws.html
enjoy