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OpenStudy (anonymous):
Suppose cosθ = 0.766 and 270° < θ < 360°. Find sinθ.
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terenzreignz (terenzreignz):
okay... first, is sin θ going to be positive or negative in that interval?
OpenStudy (anonymous):
negative
terenzreignz (terenzreignz):
Okay, good. So we can use this identity
\[\huge \cos^2\theta + \sin^2\theta = 1\]\[\huge \sin^2\theta = 1 - \cos^2 \theta\]
terenzreignz (terenzreignz):
plug in for cos θ
terenzreignz (terenzreignz):
and take the square root of both sides
\[\huge \sin \theta\]
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terenzreignz (terenzreignz):
\[\huge \sin \theta = -\sqrt{1-\cos^2 \theta}\]
(remember that sine would be negative)
OpenStudy (anonymous):
so would \[\cos ^2\] be removed and replace with 0.766? or would it be 0.766^2?
terenzreignz (terenzreignz):
0.766^2
:)
cos θ = 0.766
cos^2 θ = 0.766^2
OpenStudy (anonymous):
oooh ok
terenzreignz (terenzreignz):
Satisfied? :)
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OpenStudy (anonymous):
yep. is the answer -0.643? just to be sure?
terenzreignz (terenzreignz):
Yes.
OpenStudy (anonymous):
ok. Thank you :)
terenzreignz (terenzreignz):
Good that you understood it :)
I have to go now.
--------------------------------------------
Terence out
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