Question

Can you help mt find the solutions?
y= x²-2x-2
y+4x+5

Answer 1

no i dont im sorry.. :(

Answer 2

ok thanks anyway

Answer 3

@amistre64 can you hilp? i factored it down to x²-2x+3 but i dont know what 2 do next

Answer 4

y= x^2-2x-2
y=4x+5

since y = y, rewrite this as

x^2-2x-2 = 4x+5 , and move it all to one side

x^2-6x-7 = 0 is hat i beleive you are "stuck" at

Answer 5

ok so what do you do next?

Answer 6

well, its good to understand that multiplying is far simpler than factoring.

if this is going to factor nicely, it will have to take the form:

(x+a)(x+b)

can you expand that out for me?

Answer 7

is that the same as foiling?

Answer 8

yes, "FOIL" is a memory device used for people who forget how to multiply things together. So if you must "FOIL", then by all means do so

Answer 9

when we "foil" that general setup out, we will have something to compare our x^2 -6x -7 to

Answer 10

x²+xb+ax+ab

Answer 11

good; lets clean that up a little by combining like terms and compare it to what we have already

x^2 +(a+b)x + (ab)
x^2 + (-6) x + (-7)

we see that the sum of a and b should equal -6, and the product of a and b should equal -7

a+b = -6
ab = -7

this is the formal setup for factoring this into (x+a)(x+b)

Answer 12

the idea most books have it to do a trial and error.

determine some integer factors of -7, and see if they add up to -6

Answer 13

1 -7?

Answer 14

that would work yes :)

so let a = -7, and b=1

(x+a)(x+b) becomes (x-7)(x+1)

Answer 15

now, we want to know what this factored form is equal to zero; so solve for

x-7 = 0
x+1 = 0

and those will be the x values for the system.

the y values are simply found using one of the equation that was originally given, the linear one is simplest to solve. y = 4x+5, for each given value of x

Answer 16

ok thanks

Answer 17

so the answer is -1, 1 and 7,33?