Chandra thinks that the system of equations below has an infinite number of solutions. Do you agree with her thinking? Why or why not? 2y = x-4 -2x = -4y-8
r u sure the second equation isnt -2y = -4x - 8?
well do you agree ? @ballerina789
with @chardra -_-
No
hmm....I think so. x can be any real number in either equation. There are an infinite number of real values, so there are an infinite number of solutions. Ballerina, would that reasoning hold true?
yes
The second equation is actually supposed to be: -2x = -4y-8
They both equal y=1/2x-2
I think they actually equal: \[y=\frac{x-4}{2}\] and \[y=\frac{-2x+8}{-4}=\frac{x-4}{2}\]
no
well...if the solution is 1/(2x-2) then there will be a limit on the domain...
it could still have an infinite number of solutions (i.e. any number greater than x=something)
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