Chandra thinks that the system of equations below has an infinite number of solutions. Do you agree with her thinking? Why or why not?
2y = x-4
-2x = -4y-8
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OpenStudy (cwrw238):
r u sure the second equation isnt -2y = -4x - 8?
OpenStudy (shubhamsrg):
well do you agree ? @ballerina789
OpenStudy (shubhamsrg):
with @chardra -_-
OpenStudy (anonymous):
No
OpenStudy (anonymous):
hmm....I think so. x can be any real number in either equation. There are an infinite number of real values, so there are an infinite number of solutions. Ballerina, would that reasoning hold true?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
The second equation is actually supposed to be: -2x = -4y-8
OpenStudy (anonymous):
They both equal y=1/2x-2
OpenStudy (anonymous):
I think they actually equal:
\[y=\frac{x-4}{2}\]
and
\[y=\frac{-2x+8}{-4}=\frac{x-4}{2}\]
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
well...if the solution is 1/(2x-2) then there will be a limit on the domain...
OpenStudy (anonymous):
it could still have an infinite number of solutions (i.e. any number greater than x=something)