Question

how to take the derivative of e^x^2

Answer 1

chain rule. derivative of the outside times the derivative of the inside.

Answer 2

Is it:
\[\large e^{x^2}\]

Answer 3

\[\frac{ d }{ db }e^b = \frac{ d }{ db }(e^b) \times \frac{ d }{ db }(b)=\]

Answer 4

Not quite, @waterineyes :)
You forgot to take the derivative of "b" like in the example I provided.

You can think of it as: \(b=x^2\)

Answer 5

I just confirmed the question from asker..

Answer 6

so it will be 2e^x multiplied by e^x multiplied by 1

Answer 7

@abb0t
so it will be 2e^x multiplied by e^x multiplied by 1

Answer 8

My mistake @waterineyes

No, @0213 It is just the derivative of \(e^x\) but in this case, you have \(e^{x^2}\) so it will stay the same, multiplied by the derivative of \(x^2\)
:)

Answer 9

so e^x^2 multiplied by 2x

Answer 10

@abb0t so e^x^2 multiplied by 2x

Answer 11

Correct :)

Answer 12

Derivative of the OUTSIDE times derivative of the INSIDE \(e^x\) is the "outside" while \(x^2\) is the inside, because it's inside of another function, in this case, the exponent.

Answer 13

could you answer another question

Answer 14

Sure.

Answer 15

how

Answer 16

What do you mean how would I have?

Answer 17

sorry, my key bored is not working right. I mean how would I

Answer 18

how would i find the x-intercepts of 2xe^x^2 @abb0t

Answer 19

Set it equal to zero and solve for "x" if possible.

Answer 20

is there none because of e and the Ln of 0 is undefined

Answer 21

What about x = 0

:) Yes?

Answer 22

would I have to solve for 2x and e^x^2 as one function or two?

Answer 23

One. You can divide \(e^{x^2}\) by zero. to get 2x=0
and then get x =0