Question

help

Answer 1

write power series \[\frac{ -2 }{ 1-\frac{ x }{ 2 } }\]

Answer 2

atleast 4 terms

Answer 3

and general term

Answer 4

\[{-2\over1-{x\over2}}={-4\over(2-x)}=-4(2-x)^{-1}=-4(.....)\]
use the binomial expansion there

Answer 5

excatly i did this i took 4 derivatives at x=0

Answer 6

am i right

Answer 7

or
\[-2\left(1-{x\over2}\right)^{-1}=-2\sum_{k=0}^\infty \left(x\over2\right)^k\]

Answer 8

alright thx

Answer 9

yw

Answer 10

but you must have "x" terms
you cannot get rid of them by substituting x=0

Answer 11

so @electrokid a=-2 and r=1/2 right

Answer 12

r = {x/2}