Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

A car company tested a sports car on a road with different inclines. The test driver tested the car by driving a distance of x miles on a flat road, (x2 + 3) miles downhill, and (x - 7) miles uphill. Which simplified expression is equivalent to the total distance, in miles, for which the car was tested?

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

help!!!

jimthompson5910 (jim_thompson5910):

(x^2 + 3) + (x-7) x^2 + 3 + x - 7 x^2 + x + (3 - 7) ???

OpenStudy (anonymous):

x2 + 2x - 4?

jimthompson5910 (jim_thompson5910):

x^2 + x - 4 not sure how you got the 2x

OpenStudy (anonymous):

3x2 − 4

OpenStudy (anonymous):

thats wat i ment to put :)

jimthompson5910 (jim_thompson5910):

oh that's not correct either it should be x^2 + x - 4

OpenStudy (anonymous):

oh :( i tried thanks i only hav 2 more can u help me with them?

jimthompson5910 (jim_thompson5910):

that's ok, just keep trying and don't give up

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

Simplify the following expression: (x + 6y) - (3x – 10y). If the final answer is written in the form Ax + By, what is the value of A?

jimthompson5910 (jim_thompson5910):

(x + 6y) - (3x – 10y) x + 6y - 3x + 10y (x - 3x) + (6y + 10y) ???

OpenStudy (anonymous):

3+16y

OpenStudy (anonymous):

3x

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

x - 3x = -2x so the value of A is -2

OpenStudy (anonymous):

okay 1 more

OpenStudy (anonymous):

Simplify the following expression: (5x2 + 3x + 4) − (2x2 − 6x + 3). If the final answer is written in the form Ax2 + Bx + C, what is the value of B?

jimthompson5910 (jim_thompson5910):

you can just focus on the x terms since that's all they want 3x - (-6x) 3x + 6x ??

OpenStudy (anonymous):

9x

jimthompson5910 (jim_thompson5910):

so B = 9

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!