Question

Precalc: Law of Sines question

Answer 1

b= 2.690 i think

Answer 2

how many chances do you have left on webassingn

Answer 3

5 chances i believe but can you explain how i should start his problem?

Answer 4

i know how to do the law of sines its just getting started which is difficult for me

Answer 5

well you can take 48 as angle A and B as 32 .
because they are alternate angles( trignometry )

Answer 6

i think that should get you started

Answer 7

but they are angle depressions which arent part of the triangle

Answer 8

@jim_thompson5910 can you help me?

Answer 9

yeah but if you do it that way u get the answers , i did it that way in my precal class and i got the answer .

Answer 10

they dont have to be a part of the triangle you are using the alternate angles, it is a method through which u can find the other two angles

Answer 11

http://www.geom.uiuc.edu/~dwiggins/conj16.html
maybe this pic will make you understand better

Answer 12

and BTW sorry they are corresponding angles

Answer 13

okay thank you i will take a look at it

Answer 14

yeah i already know this but im not sure how i can link that to the triangle figure

Answer 15

angle A is 32, angle B is 48, angle C (not marked) is therefore 100

Answer 16

if we call \(\overline{AB}\) as \(c\) then the law of sines tell you
\[\frac{5}{\sin(100)}=\frac{a}{\sin(32)}\] and so you can solve for \(a\) via
\[a=\frac{5\sin(32)}{\sin(100)}\]

Answer 17

so Angle a is 32 even though the angle of depression is 32?

Answer 18

okay i understand that

Answer 19

so where would the 5 miles be? in AB?

Answer 20

i am assuming that is where the mile posts are, yes

Answer 21

okay let me calculate it

Answer 22

a=2.6904

Answer 23

if you call the distance from the plane to A \(b\) then it would be
\[\frac{b}{\sin(48)}=\frac{5}{\sin(100)}\] or
\[b=\frac{5\sin(48)}{\sin(100)}\]

Answer 24

thank you! i figured outt the other part of the problem