Ask your own question, for FREE!
Precalculus 11 Online
OpenStudy (anonymous):

The position of an object at time t is given by s(t) = 3 - 4t. Find the instantaneous velocity at t = 8 by finding the derivative.

OpenStudy (uri):

Can you take the derivative of \(s(t)\)? then sub in \(t=8\)

OpenStudy (uri):

Wait there is something wrong with this question.

OpenStudy (uri):

If you take the derivative of \(3-4t\) its \(-4\); so you cannot sub in \(t=8\)

OpenStudy (anonymous):

@uri that means, the object has a constant velocity of -4m/s (I am assuming s(t) is in meters and time in sec)

OpenStudy (uri):

But it says to find the instantenous velocity at \(t=8\). So, I assume there must be some typo by the OP.

OpenStudy (anonymous):

yes, It does seem ambiguous but is if it isnt, it might be a trick! and that is the answer!

OpenStudy (uri):

True^

OpenStudy (anonymous):

the askers should use the nice equation tool provided to enter the functions correctly and avoid confusions.

OpenStudy (uri):

But there are some users who are new to this site; so they don't know how to use it.

OpenStudy (anonymous):

yes we teach them.:)

OpenStudy (anonymous):

atleast, guide them to where it is and how they can use it.. :)

OpenStudy (anonymous):

@uri and @electrokid . Nope that's the correct equation.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!