Please Help
solve for x: 11x^2-7=2-5x^2
combine like terms if you move all the terms with x^2 to the left, and all the constant to the right what would you get?
It's like 20 something
...
-5x^2+11x^2+2-7
no first note, what happened to the equal sign 2nd note, you cannot just move terms from one side to the other you need to add/subtract that term to both sides ex. 11x^2-7=2-5x^2 say i want to move the -5x^2 to the left this can be done by adding 5x^2 to both sides because on the right, 11x^2+5x^2-7= 2 - 5x^2 + 5x^2 note on the right side, -5x^2+5x^2 =0 so we would get 11x^2+5x^2-7= 2 then we combine like terms (x^2) to get 16x^2-7= 2 now do the same thing for the constants
whats constant
constants are terms that do not have variables ex. 1 2 3 4 5 6 7 8 9 ... etc
so now I would have to add or subtract the 2 and -7
16x^2-7= 2 ok, you want to move all the constants to the side opposite to the terms with variables since the variable term is on the left side, you want to move all the constants to the right side
I just don't understand how to move all the constants to the right side
since 2 is already on the right side, you dont need to do anything with it you want to move the -7 over to the right side, what would you have to add/subtract in order to achieve this?
read over the steps i did for moving the variable terms to the left side
still no idea?
so the first step is 11x^2-7+7=2-7-5x^2
Might this help at all: http://openstudy.com/study#/updates/516cac51e4b063fcbbbca4f1 ?
almost, since you added 7 to the left side, you also need to do the same to the right side if you do something to one side, you need to do the same thing to the other
first step would look like 11x^2-7+7=2+7-5x^2
ok so 11x^2-7+7=2-7+7-5x^2
i gave you the first step, compare it to the original equation and tell me what is different
I did the first one the same thing that you did 11x^2-7+7=2-7-5x^2
no you didnt you have a -7 on the right side i have a +7 on the right side you need to add 7 to both sides in order to cancel out the -7 on the left side
ok so 16x=3
sorry i lied thats completely wrong go back a step 16x^2= 9
first divide by 16 to both sides
16 and 9 /16?
16/16=1 dividing 16 to both sides would give you x^2=9/16
so now divide 9/16 by 2?
no you need to find the square root of both sides
sqrt of 9 and 16?
sqrt of 9/16
9=3,,16=4
\[x^2=\frac{9}{16}\] \[\sqrt{x^2}= \sqrt{\frac{9}{16}}\] \[\sqrt{x^2}=x\]
so whats the answer
whats x
well sqrt of 9 is 3 and the sqrt of 16 is 4 3/4
there are 2 solutions for x
so 3/4 is the answer?
3/4 is one of them what is the other
ok thanks
note a negative number squared is positive the other answer would be -3/4
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