Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Differentiate: (x^2 + 5x + 6) / (x+2)

hartnn (hartnn):

differentiating will greatly simplify if you could simplify (x^2 + 5x + 6) / (x+2) first. can you factor (x^2 + 5x + 6) ??

hartnn (hartnn):

@jessie096 i assume you are trying.

OpenStudy (anonymous):

Quotient rule. Derivative is equal to ((2x+5)(x+2)-(x^2+5x+6))/(x+2)^2

hartnn (hartnn):

why go into complications when not required....

OpenStudy (anonymous):

(u'v-v'u)/v^2

OpenStudy (anonymous):

try to factor out first x^2 + 5x + 6..

hartnn (hartnn):

did you try factoring the numerator ro see what happens ?

hartnn (hartnn):

@jessie096 can you factor x^2+5x+6 ?

OpenStudy (anonymous):

yes it's 2x+5

hartnn (hartnn):

umm...you differentiated the numerator, i asked you to 'factor' it.

OpenStudy (anonymous):

(x-2)(x-3)

hartnn (hartnn):

oh, you sure you didn't mess up with signs ? can it be (x+2)(x+3) ?

OpenStudy (anonymous):

oh yeah sorry

hartnn (hartnn):

ok, no problem :) so (x+2)(x+3) is numerator, anything getting cancelled ??

OpenStudy (anonymous):

yep wow that was pretty easy....the (x+2) cancel out and you're left with (x+3) which is differentiated to 1 :D thanks so much

hartnn (hartnn):

good! its \(\huge \color {green }\checkmark\)

hartnn (hartnn):

\[ \begin{array}l\color{red}{\text{w}}\color{orange}{\text{e}}\color{#e6e600}{\text{l}}\color{green}{\text{c}}\color{blue}{\text{o}}\color{purple}{\text{m}}\color{purple}{\text{e}}\color{red}{\text{ }}\color{orange}{\text{^}}\color{#e6e600}{\text{_}}\color{green}{\text{^}}\color{blue}{\text{}}\end{array} \]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!