Check whether f(x)=1/x is continuous or not ?
What happens if x=0?
There is an asymptote (vertical)
For a function to be continuous, http://www.cliffsnotes.com/study_guide/Continuity.topicArticleId-39909,articleId-39876.html Does f(0) exist, for f(x)=1/x?
so lim x->0 does not exist bcoz LHL = -infinity and RHL = infinity ?
That too, but is the first condition even met? Does f(0) exist?
If f(0) = infinity, can we say f(0) exists ? :P
haha, we can not :P So f(0) does not exist, and the limits at the left and right are not equal (and they also do not equal f(0), because... it doesn't exist!)
Okayy! Dumb me
You can't really even say f(0) = infinity even in terms of the limits (f(0) is just undefined), since it approaches -inf from the left, and +inf from the right, compared to something like 1/x^2, which approaches +inf from both the left and right (1/x^2 is still undefined for x=0, since a function can't actually be equal to infinity... it can just approach it)
ouch.. Thanks you rock
You can also plot it on google: https://www.google.com/search?q=1%2Fx&aq=f&oq=1%2Fx&aqs=chrome.0.59l2j58j5j0j62.2465j0&sourceid=chrome&ie=UTF-8
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