Question

I know this is a long shot, but I believe I have a genius out there.
use long division to find the quotient of the following problem.
(12x3 + 9x - 11x2 + 19) / (4x + 3)
(the 3 and 2 in this problem are hypen 3 and 2)

Answer 1

start with
\[\frac{12x^3 + 9x - 11x^2 + 19}{4x + 3}\]
\[=\frac{12x^3-11x^2+9x+19}{4x+3}\] then if you can factor the numerator you can cancel, if not, you have to divide using long division

Answer 2

actually forget the part about factoring, since 3 does not divide 19
you are going to do long division for this one, which i find impossible to write here

Answer 3

no it is not \(\frac{2(5x+7)}{4x+3}\)

Answer 4

can you send it to me?

Answer 5

the answer i can send you instantly
the method you need pencil and paper for

Answer 6

Would love both w/the hopes of learning how to do it, but right now any thing you can send would help.

Answer 7

chris-j@comcast.net

Answer 8

the answer is
\[3x^2-5x+6+\frac{1}{4x+3}\]

Answer 9

the method is to divide as you would with numbers

Answer 10

use the chris email. hmmm, would love to know the long version.

Answer 11

ok, any more tips, I really need to know how to do this.

Answer 12

that is the first step, it is just like dividing numbers

Answer 13

think like this:
\(4x\) goes in to \(12x^3\) \(3x^2\) times just as you would with whole numbers
then put the \(3x^2\) up top, multiply \(3x^2\times (4x+3)=12x^3+9x^2\) put that underneath, then subtract