Question

Write the polynomial
4x^2 + x^5 - 12 + 6x in standard form.

A. 4x^2 + x^5 - 12 + 6x

B. x^5 + 4x^2 +6x - 12

C. -12 +6x 4x^2 + x^5

D. x^2(4 + x^3) + 6(x - 2)

Answer 1

\[x^5 + 4x^2 + 6x -12\]
Standard form means that the terms are in order from highest to lowest degree.

Answer 2

so Answer is B :D !

Answer 3

seems pretty self-explanatory. To put an equation into standard form (depending on your definition of standard form), all you have to do is arrange the terms (meaning anything that is separated by a plus or minus) in terms of highest degree. In this case we have the terms:

\[{4x^2}\]
\[x^5\]
\[-12\]
and
\[6x\]
our highest degree is the term with the highest power. You can see in the above terms that \[x^5\] has the highest power; therefore, it will be first. Can you see where the rest of antoni's terms came from?

x^5 is power 5
4x^2 is power 2
6x is power 1
and -12 is power 0. If you don't understand what I mean by power 0, you may not have learned that concept yet. You will learn that x^0=1 so -12*x^0=-12*1=-12.

Regardless,

your answer will go from power 5 to 2 to 1 to 0:

standard form:
\[f(x)=x^5+4x^2+6x-12\] B is your answer