Question

solve in steps sec(xy) = y find dy\dx?

Answer 1

@syltan do u have any idea how r u going to approach this prob?

Answer 2

if u want any help u need to cooperate

Answer 3

@niksva
i try to use implicit differentiation to this problem and i get:
dy\dx=sec(xy)tan(xy)*(y+x*dx/dy)

but i am not sure i write am I.

Answer 4

1) dy/dx = y/1-e^x

=> (1/y) dy = (1/1-e^x) dx

integrate both sides u get :

ln|y| = S (1/1-e^x) dx

let u = 1-e^x

=> du = - e^x dx = (u-1) dx

=> ln|y| = S 1/u(u-1) du

hope it helps

Answer 5

@syltan
u just made the little mistake in the end
u r going to get
\[\frac{ dy }{ dx } = \sec(xy) \tan(xy) ( y + x \frac{ dy }{ dx })\]