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how do I solve logv4 (y - 9) + logv4 3 = logv4 81?
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\[\log _{4} (y-9)+\log _{4} 3=\log _{4} 81\]
First you use the following rule of logs on the left hand side: \[\log_{a} b+\log_{a} c=\log_{a} (b \times c)\] Can you do that?
so \[\log _{4} (3y-27)=\log _{4} 81\]
Good work! Now we can state the following: 3y - 27 = 81 and solve for y.
@DeadShot Are you there?
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Sorry, I'm taking care of my sick little brother while my parents are away, so y=36, right?
Your answer is correct :)
okay, thanks!
You're welcome :)
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