Ask your own question, for FREE!
Chemistry 24 Online
OpenStudy (e.cociuba):

Which is more concentrated: a 1.0 L solution with 20g of sucrose, C12 H22 O11, or a 1.0 L solution with 20 g of glucose, C6 H12 O6? Explain.

OpenStudy (e.cociuba):

@electrokid

OpenStudy (anonymous):

did you calculate the molarities?

OpenStudy (anonymous):

see.. isnt hard to tag people .. :P

OpenStudy (e.cociuba):

Haha ya but when they ignore u, it is.. lol

OpenStudy (anonymous):

yep. math is easy.. everybody just plays with numbers.. when it comes to applications, thats when people ___ in pants

OpenStudy (anonymous):

ok, so what about the molarities here?

OpenStudy (anonymous):

molar mass of sucrose = \(12(12)+22(1)+11(16)=?\) molar mass of glucose = \(6(12)+12(1)+O(6)=?\)

OpenStudy (e.cociuba):

Ok so when u mean molarity, do u mean this: (12)(12.01) + (22)(1.008) (11)(16.00) ---------

OpenStudy (anonymous):

yep-> thats molar mass

OpenStudy (e.cociuba):

Ok so I got 342.298...

OpenStudy (anonymous):

good so, 342.3g of sucrose = 1mole therefore, 20g of sucrose = ? moles?

OpenStudy (anonymous):

20g of sucrose = \(\Large{20\over342.298}=?\)

OpenStudy (e.cociuba):

Isn't 1 mole supposed to be on top?

OpenStudy (e.cociuba):

Oh wait nvm oops Now I see..

OpenStudy (anonymous):

by proportionality, if 342.298 g = 1mole, then 30g would be less than 1mole

OpenStudy (anonymous):

so, how many moles of sucrose would that be?

OpenStudy (e.cociuba):

Ok now tht just confused me... srry..

OpenStudy (anonymous):

dont worry. you understand that you'd have to divide, right?

OpenStudy (e.cociuba):

yup

OpenStudy (e.cociuba):

|dw:1366141870311:dw| I thought this is how u do it, cuz the grams have to cancel out??

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!