Question

I have problem with Gram-Schmidt process when orthonormal vector, someone shows me steps, please
if I have 2 vectors like v1=( -1,1,0) and (-1,0,1) . How to work with them?

Answer 1

Look at the commentary underneath this Khan Academy video. It may be of help.

http://www.khanacademy.org/math/linear-algebra/alternate_bases/orthonormal_basis/v/linear-algebra--gram-schmidt-process-example

Answer 2

Thanks Directrix.

Answer 3

oh, I cannot let it run. that problem happen to my computer long time ago, i don't know how to fix it

Answer 4

ok, i can use youtube, thanks

Answer 5

:) I went to Khan academy. but the window stuck with black screen . I don't know how run the video tapes. All things seem good, I can click any button and I get it but not video tape. they didn't run .
I got what you mean from the material

Answer 6

Can you see the discussion underneath the video player that will not work? If not, I will paste it here for you.

Answer 7

no, send me, please

Answer 8

oh, I see.

Answer 9

the note about this. ok, I got it.

Answer 10

just note a tape. hhmmm,

Answer 11

thnks a lot. I will find out the way to make the tape run. (later, not now)

Answer 12

http://www.youtube.com/watch?v=tu1GPtfsQ7M

http://www.youtube.com/watch?v=rHonltF77zI

Answer 13

thank you very muuuuuuuch

Answer 14

There are more over there. I don't mind looking for them to help. (as long as I don't have to view them) :)

Here's Dr. Bob http://www.youtube.com/watch?v=KKffS_U6_34

Linear Algebra: Construct an orthonormal basis of R^3 by applying the Gram-Schmidt orthogonalization process to (1, 1, 1), (1, 0, 1), and (1, 1, 0). In addition, we show how the Gram-Schmidt equations allow one to factor an invertible matrix into an orthogonal matrix times an upper triangular matrix.

Answer 15

I got it. Thnks a lot. You spend too much time to help others. Appreciate

Answer 16

Is the information at this link of any help: http://tinyurl.com/coa957c

I do not know what the specific question you have is or I would look for that.

One thing I can do is to help you search.

Answer 17

That's enough, Thanks for help. Of course, I have to understand what it is, not just get the answer.