Can we solve this? 1 ∫ (x ln x )dx 0
\[\int\limits_{1}^{0} x lnx dx\]
parts is my guess
improper integral, so it may not exist, but you can find the anti derivative by parts and then check
ooh that was wrong sorry
we can solve it
\[\int udv = uv-\int vdu\] with \(u=\ln(x), du =\frac{dx}{x}, dv = x, v = \frac{x^2}{2}\) should do it
"anti derivative" will be \[\frac{x^2}{2}\ln(x)-\frac{x^2}{4}\] i think
now you are going to need to find that \(\lim_{x\to 0}\frac{x^2}{2}\ln(x)=0\)
I know that we can solve it by parts, but due to it's definite integral 0 and 1, so i think ln(0) is not possible.
when i tried this in wolfrom mathematica, it was giving answer of -1/4.
like satellite73 said, that's the answer... what you have to do is, find the limit \[\lim_{x \rightarrow 0} \frac{ x^{2} }{ 2 } \ln x\]... I think that's done if you know logarithmic series...
and you use L'Hopital's rule then.. try plugging in the logarithmic infinte series for log x...hope this hint helps..
thanks
welcome :)
hey, can u say, how to apply L'Hospital's Rule in finding Log[0]?
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