Show that R={( a 0 / b c)} | a,b, c are elements of Z} i a ring with identity. a 0 / b c is the matrix with a 0 the first row and b c the second row.
also show that the map f:R -> Z given by f(a 0 / b c) = a is a surjective homomorphism. What is the kernal of f?
What does a 0 / b c mean?
i didnt know how to make the matrix \[\left[\begin{matrix}a & 0 \\ b& c\end{matrix}\right]\]
apparently, now you do :D
well on the initial input math they dont give you the equation tools
You have to memorise a few LaTeX tricks... but let's focus on your question, shall we? :)
yes please
You know how to multiply matrices?
yes
Well, then, for your first question, your only charge is pretty much to show closure... and show that matrix multiplication distributes over matrix addition... have you done this already?
I can show closure but you'll have to elaborate on distributes over addition
I mean, show that for 2x2 matrices A,B, and C A(B + C) = AB + AC (B + C)A = BA + BC
oh show distribution okay
that proves identity though?
That's one of the ring-axioms, right? :D
okay okay we are going to prove its a ring and then prove it has identity. I was going too far
So you have it from here?
except also show that the map f:R -> Z given by f(a 0 / b c) = a is a surjective homomorphism. What is the kernal of f?
Is it a homomorphism, though? Show that first...
show that for any two matrices A and B in R f(A + B) = f(A) + f(B) and f(AB) = f(A)f(B) That should be enough to show homomorphism-ness :D
how do i determine the kernel?
Kernel is simply the subset of R which is mapped to 0... namely, those 2x2 matrices which have 0 for their upper-left entry :)
oh yeah thanks! I should be able to do it from here. I think I was just trying to over complicate it.
No problem :)
wait! how to I know its surjective? I mean to me it looks obvious that it is an onto function but is there a formal way to show this?
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