Question

math

Answer 1

Find the volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm. (1 point)11,520 cm3
23,040 cm3
7,680 cm3
768 cm3

Answer 2

find volume . 108.9 in.3
707.9 in.3
1,061.9 in.3
2,123.7 in.3

Answer 3

the volume of a square pyramid is \[\frac{ l^2 }{ 3 }*h\]
where l is the slant height. in this case the issue is to find the height which you can do using pythagoras theorem. so you first find \[(\sqrt{48^2+48^2})/2\]
and you get 33.9411. then your h you get it by \[\sqrt{26^2-33.9411^2}\]
and oops you get an unsolvable equation. I don't know if this is the correct info?

Answer 4

for the first one,
use the above formula
\[V={1\over3}l^2h\]

for the second one, understand that the complete volume of the cylinder is split into two identical volumes.
volume of cylinder = \(\pi r^2h\)

Answer 5

im still slighty confused .

Answer 6

with which one

Answer 7

the second

Answer 8

and sum of both equals the volume of the right circular cylinder

Answer 9

Im not getting a correct answer .

Answer 10

what value did you get

Answer 11

i did 16*16*13 and 13*13*16 ad neither were correct

Answer 12

what is the "radius" of the circular base??

Answer 13

it is half of 13.... 13 is the diameter...
\[V_{\rm cylinder}=\pi\left(13\over2\right)^2\times16\]

Answer 14

and the volume of the region is HALF of that

Answer 15

?

Answer 16

kapeesh, Ambassador?