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Mathematics 18 Online
OpenStudy (anonymous):

The polygons are regular polygons. Find the area of the shaded region to the nearest tenth.

OpenStudy (anonymous):

OpenStudy (anonymous):

@dmezzullo i need help

OpenStudy (anonymous):

please help

OpenStudy (anonymous):

We need one more constraint for this to be possible.

OpenStudy (anonymous):

what do you mean this is all the problem is

OpenStudy (anonymous):

Unless I'm missing something (which could be the case), there needs to be an extra constraint...

OpenStudy (anonymous):

this is all it gave me

OpenStudy (anonymous):

please help

OpenStudy (anonymous):

I reckon I can have a crack if you still need help?

OpenStudy (anonymous):

i need help

OpenStudy (anonymous):

Ok, so I think we can break down the shapes in to two squares and 2 triangles.|dw:1366259113710:dw|We know the length of the diagonal side, which is 4. With me so far?

OpenStudy (anonymous):

still with you

OpenStudy (anonymous):

Great, we also know that the sides of a square are all the same. Let's call them \(x\)|dw:1366259222870:dw|Looking at the triangle with the sides I have marked x, we can use Pythagoras to calculate x. |dw:1366259261591:dw|What is the value of x?

OpenStudy (anonymous):

4

OpenStudy (anonymous):

Nope use Pythagoras' theorem.\[a^2+b^2 = c^2\]In this case our value for c is 4. And our value for a and b is x, making our equation\[x^2+x^2 = 4^2\]Does that make sense?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Ok, so what do you get for x?

OpenStudy (anonymous):

2x^2=16 right

OpenStudy (anonymous):

So far so good

OpenStudy (anonymous):

then do you divide 2 to make x^2=8

OpenStudy (anonymous):

yep making x...?

OpenStudy (anonymous):

x=64

OpenStudy (anonymous):

No, square root both sides. \[x^2=8 \rightarrow \sqrt{x^2}=\sqrt{8}\] Making \[x=\sqrt{8}\]

OpenStudy (anonymous):

Oh, crap, missed the whole first part of the case "regular polygons." Thanks, mate, for catching that!

OpenStudy (anonymous):

No probs

OpenStudy (anonymous):

Does that make sense @sandbeach ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Great now we know the length of the square, we can think of the shaded region as simply three identical squares with length \[\sqrt{8}\]. Do you know how to find the area of a square?

OpenStudy (anonymous):

lenth x width

OpenStudy (anonymous):

Awesome, so what is the area of one of these squares of length \(\sqrt{8}\)?

OpenStudy (anonymous):

i dont know the anser to sqrt8 x 4

OpenStudy (anonymous):

I have to go now, but basically the size of a square of length \(\sqrt{8}\) is 8. We know that there are 3 squares making up our shaded region. \[3 \times 8 = 24\] That is your answer.

OpenStudy (anonymous):

so that is the area to the shded region

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