Question

If f(x)=square root 6sin(x)+9 then f'(0)=

Answer 1

\[\sqrt{6\sin(x)+9}\]

Answer 2

\[f(x)=(6\sin{x}+9)^{\frac{ 1 }{ 2 }}\]\[f'(x) = \frac{ 1 }{ 2 }(6\sin{x}+9)^{\frac{ -1 }{ 2 }} \times 6 \cos {x}\]Hence f'(0) =1

Answer 3

so then the answer is 1 correct?

Answer 4

@Anonymous1921 is that the correct answer that I posted just making sure

Answer 5

1 is the answer right?

Answer 6

Yep.

Answer 7

ok thanks