Question

Can somone please help me with this.....

Answer 1

Yeah.

Answer 2

There is another copy of it

Answer 3

Oh well the first picture is not the same as the first but I'm guessing it the second picture you actually need help with.

Answer 4

yes the second one is the question exactly

Answer 5

Suppose \[x \ne -3~then~f(x)=\frac{x^2-9}{x+3}=x-3\]Now take the limit\[\lim_{x \rightarrow -3}(x-3)=-6=k\]

Answer 6

That will give continuity

Answer 7

ok I am following but are you saying that the answer is -6

Answer 8

I think so....

Answer 9

ok cause I got 3 but what you are saying looks right I think

Answer 10

@jdoe0001 does that answer look right

Answer 11

We are all just doing our best here....

Answer 12

Do math every day.

Answer 13

I know

Answer 14

that looks right to me, is what I got, yes, K=-6 will make it continuos

Answer 15

ok thanks for double checking