Question

i need some math help

Answer 1

Sorry got distracted, but before I begin, is the symbol just to the right of the closing parenthesis a + or a division symbol?

Answer 2

+

Answer 3

ok thanks, wasn't sure

Answer 4

Here's how I would simplify


\[\Large \left(\frac{x}{x-4}+\frac{6}{x+4}\right) + \frac{3}{2x^2-32}\]


\[\Large \left(\frac{x}{x-4}+\frac{6}{x+4}\right) + \frac{3}{2(x^2 - 16)}\]


\[\Large \left(\frac{x}{x-4}+\frac{6}{x+4}\right) + \frac{3}{2(x-4)(x+4)}\]


\[\Large \frac{x}{x-4}+\frac{6}{x+4} + \frac{3}{2(x-4)(x+4)}\]


\[\Large \frac{2x(x+4)}{2(x-4)(x+4)}+\frac{6}{x+4} + \frac{3}{2(x-4)(x+4)}\]


\[\Large \frac{2x(x+4)}{2(x-4)(x+4)}+\frac{6*2*(x-4)}{2(x-4)(x+4)} + \frac{3}{2(x-4)(x+4)}\]


\[\Large \frac{2x(x+4)+6*2*(x-4)+3}{2(x-4)(x+4)}\]


\[\Large \frac{2x(x+4)+12(x-4)+3}{2(x-4)(x+4)}\]


\[\Large \frac{2x^2+8x+12x-48+3}{2(x-4)(x+4)}\]


\[\Large \frac{2x^2+20x-45}{2(x-4)(x+4)}\]

Answer 5

thank you sooooo muh!!!

Answer 6

sure thing