Question

help me but dont give me the answer plz

Answer 1

sure

Answer 2

8-4/3(-4/3 is a fraction)

Answer 3

well make 8 into a fraction with the same denominator(3)

Answer 4

24/3?

Answer 5

yupp! so then just do 24/3-4/3 which gives you?

Answer 6

combind them?

Answer 7

no subtract them..

Answer 8

20/3?

Answer 9

yupp! :D

Answer 10

okay thats not correct... None of the answer say that :/

Answer 11

did you copy it down right?

Answer 12

you may have to convert to a mixed number

Answer 13

16
-16
-1/16
1/16

Answer 14

did you copy it down right? 8-(4/3)

Answer 15

yeah.

Answer 16

@jim_thompson5910 do you have any ideas?

Answer 17

(-4/3)

Answer 18

8-(-4/3)?

Answer 19

so is it 8 times (4/3) ?

no that wouldn't work either

Answer 20

No the fractions a negative

Answer 21

8 divided by -4/3 maybe

Answer 22

ooooh, 8 to the 4/3 power

Answer 23

OHH!

Answer 24

-4/3 power i mean

8^(-4/3) = 1/(8^(4/3))

Answer 25

idk this pellet fluttering sucks like i said @jim_thompson5910

Answer 26

8^(-4/3) = 1/(8^(4/3))

8^(-4/3) = 1/((cube root of 8)^4)

8^(-4/3) = ???

Answer 27

i completely lost

Answer 28

\[\Large 8^{-4/3} = \frac{1}{8^{4/3}}\]


\[\Large 8^{-4/3} = \frac{1}{\left(\sqrt[3]{8}\right)^4}\]


\[\Large 8^{-4/3} = ??\]

Answer 29

i don't know. like never learned this. ummm \[(2\sqrt[3]{4})^{4} \] I feel i did that wrong

Answer 30

the cube root of 8 = ???

Answer 31

I give up. forget it. one wrong answer wont kill me. this is giving me a big headache and im flipping beyond sleepy.. thanks tho. :)

Answer 32

ok I'll finish it up


\[\Large 8^{-4/3} = \frac{1}{8^{4/3}}\]


\[\Large 8^{-4/3} = \frac{1}{\left(\sqrt[3]{8}\right)^4}\]


\[\Large 8^{-4/3} = \frac{1}{2^4}\]


\[\Large 8^{-4/3} = \frac{1}{16}\]

Answer 33

The cube root of 8 is 2 since 2^3 =8

Answer 34

are you for real. I feel stupid :(

Answer 35

don't be, you probably made a silly mistake

Answer 36

yeah taking an exam while hardly awake was a silly mistake!