Question

help!! how do i solve for n in:

(.9985atm)(.02L)= (0.082 atm*L/mole*K)(296K)

sooo stumped!!!

Answer 1

(.9985atm)(.02L)= n (0.082 atm*L/mole*K)(296K)

n=[(0.082 atm*L/mole*K)(296K)]/[(.9985atm)(.02L)]

Answer 2

i cant get a definite number/figure for n tho? i dont understand how to caclulate 0.082 atm*L/mole*K or what it means

Answer 3

its PV =nRT
n=PV/RT
= .9985atm *02L / 0.082 atm*L/mole*K *296K
= find it

atm*L/mole*K its just unit of gas constant
don't worry about it

Answer 4

@missy101 got it ???:)

Answer 5

@aaaronq is wrong !!!

Answer 6

my baddd i copied and pasted backwards

Answer 7

its all right it happens some times !!!:)

Answer 8

when you go out on a limb, you sometimes fall off the tree. it's really minor anyway.

Answer 9

CAN YOU PLEAE HELP ME

Answer 10

hmmm ok so theres no specific answer? i was told i needed to find one. . . dont see how its posible :/

Answer 11

if you want the numbers, give me a sec.

Answer 12

8.2 10^-4 is answer LOL:)

Answer 13

you want the number of gas particles in moles, or n. using the ideal gas law:

n = P V / (R T)

putting everything in atm, L, and K:

n = (.9985 * .02) / (0.082 * 296) mol

it comes out to be 8.2 x 10(-4) mol, just like chmvijay posted