solve using the quadratic formula leave in simplified form
5x^2-3x-3=0
how would i do this?

Question

solve using the quadratic formula  leave in simplified form
5x^2-3x-3=0 
how would i do this?

anonymous · Answer

$$\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$ with $a=5, b=-3, c=-3$

anonymous · Answer

you get 
$$\frac{3\pm\sqrt{(-3)^2-4\times 5 \times (-3)}}{2\times 5}$$ as a first step

anonymous · Answer

i got 
$$3\pm \sqrt{-51\div10}$$

anonymous · Answer

some mistake inside the radical

anonymous · Answer

$$\frac{3\pm\sqrt{9+60}}{10}$$

anonymous · Answer

oh right a - times a - is a positive 
$$3\pm \sqrt69/10$$

anonymous · Answer

that is it

anonymous · Answer

thats the quadratic formula?
i know that what they give us os we have to plug it in to the original formula 
but the way u showed me is reallly simple thank you so so much :D

anonymous · Answer

yes, that is the quadratic formula
don't forget that EVERYTHING  is divided by $2a$ not just the stuff in the radical

anonymous · Answer

yw

anonymous · Answer

everything thats on top of it right

anonymous · Answer

yes, it is all on top of $2a$ 
exactly as i wrote in the first post

anonymous · Answer

alright got it 
thanks a bunch once again :)

anonymous · Answer

yw (again)

anonymous · Answer

:D