differentiate F(x) = xe^-x^2
= xe^-x^2 (-2x)
F(x) =-2x^2 e^-x^2
is that the answer

Question

differentiate  F(x) = xe^-x^2
                             = xe^-x^2 (-2x)
                     F(x)  =-2x^2 e^-x^2
is that the answer

tkhunny · Answer

This  $\dfrac{d}{dx}xe^{-x^{2}}$?

anonymous · Answer

you've got to use the product rule because there are two functions of "x" multiplying 
and then during evaluation, you will have to use the chain rule in one of the steps

anonymous · Answer

$$x(e ^{-x^2})(-2x)+(e ^{-x^2})(1)$$
answer
$$-2x^2(e ^{-x^2})+e ^{-x^2}$$

tkhunny · Answer

You may wish to rewrite a bit: $e^{-x^{2}}(1-2x^{2})$

anonymous · Answer

where the one coming from?

tkhunny · Answer

Multiplication?  Consult the Distributive Property of Multiplication over Addition.

fibonaccichick666 · Answer

ok so if tkhunny is correct on the notation, it may help to think of it in terms of a substitution: so 
$$\frac{d}{dx} xe^{x^2}=x(e^u du)$$
applying the chain rule: $$=e^u+xe^udu$$
$$=e^{x^2}+x*2x*e^{x^2}$$
$$=e^{x^2}[1+2x^2]$$ do you understand?

anonymous · Answer

yes thank you to all of you

tkhunny · Answer

...well, with a few negative signs in there.