Question

Find the indicated limit, if it exists.

Answer 1

Try the LHL and RHL concepts again taking 5-x in LHL and x+3 in RHL ..!

Answer 2

What do I plug in as x?

Answer 3

5?

Answer 4

We assume a small decrement 'h' from 5.. when h->0, x->5
LHL = lim(h->0) 5-(5-h) =5-5+h = 0
Simlarly we assume a small increment 'h' from 5.. when h->0, x->5
RHL = lim(h->0) 5+h+5 = 10
Since LHL != RHL, limit does not exist... It approches 0 from left, 10 from right and has a value of 8 at x=5.. got it ? :P

Answer 5

Ok!

Answer 6

Great.! =)