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OpenStudy (anonymous):
Find the coefficient of x^8 in
(x^4 +x^5 + x^6)(x^3 +x^4 +x^5) (1+x+x^2+x^3+.....) Use generating function
Please, help
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OpenStudy (anonymous):
any idea, friend
OpenStudy (amistre64):
youd have to teach me what a generating function is
OpenStudy (anonymous):
lol... don't tease me, please
OpenStudy (amistre64):
im sure i can come up with a coeff, but with a different method
OpenStudy (anonymous):
ok, tell me yours
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OpenStudy (amistre64):
x^4 +x^5 + x^6
x^3 +x^4 +x^5
----------------
x^7+x^8+x^9
x^8+x^9+x^10
x^9+x^10+x^11
--------------------------
x^7 + 2x^8 + other stuff that will go above x^8
OpenStudy (amistre64):
1+x+x^2+x^3+.....
x^7+2x^8
--------------
x^7+x^8+x^9+x^10+.....
+2x^8+2x^9+...
-------------------
3x^8
OpenStudy (anonymous):
got it, friend
OpenStudy (anonymous):
thanks a lot. sorry, I didn't realize that you got the final answer. Lol .
OpenStudy (anonymous):
one more question. if jx^7/1-x =\[\sum_{k=0}^{\infty}\left(\begin{matrix}k+1 \\ 1\end{matrix}\right)x^k+7\]
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OpenStudy (anonymous):
the last one is x^(k+7)
OpenStudy (anonymous):
sorry, my bad computer. x^7 / 1-x = sum (k+1 choose 1) of x^(k+7)
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