√(5 √(5 √(5 √(5)))) solve
\(\sqrt{(5\sqrt{(5\sqrt{(5\sqrt{5})))}}}\) Right?
\(\begin{array}{}(5\sqrt{5\sqrt{5\sqrt{5}}})^{\cfrac{1}{2}}\\ (5\times 5 \sqrt{5\sqrt{5}})^\cfrac{1}{4}\\ (5\times 5\times 5 \sqrt{5})^\cfrac{1}{8}\\ (5\times 5\times 5\times 5)^\cfrac{1}{16}\\ \end{array}\)
\[= \left(5^4\right)^{\large \frac{1}{16}}\]
@k.m.imran can you solve it now?
i think its should to be : \[\sqrt{5*\sqrt{5*\sqrt[4]{5^{3}}}}=\sqrt{5*\sqrt[8]{5^{7}}}=\sqrt[16]{5^{15}} = 5^{\frac{ 15 }{ 16 }}\]
hey @mathslover mmm my answer is wrong? :-?
Not sure horotat, we need the asker's interaction at this time.
@mathslover at last what is the correct answer?
its a wrog answer seems
@k.m.imran you mean \[5^{\frac{ 15 }{ 16 }}\] is incorrect?
for five square root of 5 answer is \[5^{31/32}\]
:-? what is incorect in my answer?
hey could you explain me how you got that??? @horotat your answer is correct
Ok! Horotat, good work dude.
i written my complete answer a little upper :-? you see that?
HOW DID U GOT
\[5^{15}\]
\(\sqrt{5\sqrt{5 \sqrt{5\sqrt{5}}}}\) Is this the question @k.m.imran ?
rewrite using rational exponents starting inside we have (5(5(5(5)^1/2)^1/2)^1/2)^1/2
yes @mathslover
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