Question

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Answer 1

\[\newcommand % new commands % parameters %
\p \newcommand
\p \q \renewcommand
\p \eo { \varepsilon_{o}^{} } % electric constant
\p \mo { \mu_0^{} } % magnetic constant
\p \co { c_0^{} } % speed of light in vacuum

\p \E { \mathcal E } % electromotive force
\p \eell { \boldsymbol{ \ell} } % length vector

\p \mx { _\text{max} } % maximum value
\p \fr { _\text{free} } % maximum value
\p \ind { _\text{ind} } % induced
\p \enc { _\text{enc} } % enclosed
\p \pn { _\text{pen} } % penetrating
\p \os { _\text{open surface} } % open surface
\p \cs { _\text{closed surface}} % closed surface
\p \ol { _\text{open loop} } % open loop
\p \cl { _\text{closed loop} } % closed loop


\p \ve [1] { \vec{\boldsymbol{#1} } } % vector
\p \uv [1] { \hat{\mathbf #1} } % unit vector
\p \dd [1] { \,\mathrm d#1 } % infinitesimal
\p \intl [4] { \int\limits_{#1}^{#2}{#3}{\dd #4} } % integral ∫_a^b{f(x)} dx
\p \de [2] { \frac{ \mathrm d #1}{\mathrm d#2} } % first order derivative


\begin{align} % table %
&\boxed{ \oint\limits\cs\hspace{-1.5em}\ve E\cdot\dd\ve A
= \frac{\sum Q\enc}\eo }
&\text{Gauss's law} \\
&\boxed{ \oint\limits\cl\hspace{-1em}\ve B\cdot\dd\ve \eell
= \mo I\pn }
&\text{Ampè}\grave{\text e}\text{re's circuital law} \\
&\boxed{ \oint\limits\cs\hspace{-1.5em}\ve B\cdot\dd\ve A
= 0 }
&\text{Gauss's law for magnetism} \\
&\boxed{ \oint\limits\cl\hspace{-1em}\ve E\cdot\dd\ve \eell
= -\de{}t\hspace{-1em}\int\limits\os\hspace{-1.5em}\ve B\cdot\dd\ve A}
&\text{Faraday's law ofa induction}
\end{align}


\]

Answer 2

[\newcommand % new commands % parameters %
\p \newcommand
\p \q \renewcommand
\p \eo { \varepsilon_{o}^{} } % electric constant
\p \mo { \mu_0^{} } % magnetic constant
\p \co { c_0^{} } % speed of light in vacuum
\p \E { \mathcal E } % electromotive force
\p \mx { _\text{max} } % maximum value
\p \fr { _\text{free} } % maximum value
\p \enc { _\text{enc} } % enclosed
\p \pn { _\text{pen} } % penetrating
\p \os { _\text{open surface} } % open surface
\p \cs { _\text{closed surface}} % closed surface
\p \ol { _\text{open loop} } % open loop
\p \cl { _\text{closed loop} } % closed loop
\p \ve [1] { \vec{\boldsymbol{#1} } } % vector
\p \dd [1] { \,\mathrm d#1 } % infinitesimal
\p \de [2] { \frac{ \mathrm d #1}{\mathrm d#2} } % first order derivative
\begin{align} % table %
&\boxed{ \oint\limits\cs\hspace{-1.5em}\ve E\cdot\dd\ve A
= \frac{\sum Q\enc}\eo }&\text{Gauss's law} \\
&\boxed{ \oint\limits\cl\hspace{-1em}\ve B\cdot\dd\ve \ell
= \mo I\pn }&\text{Ampere's circuital law} \\
&\boxed{ \oint\limits\cs\hspace{-1.5em}\ve B\cdot\dd\ve A
= 0 }
&\text{Gauss's law for magnetism} \\
&\boxed{ \oint\limits\cl\hspace{-1em}\ve E\cdot\dd\ve \ell
= -\de{}t\hspace{-1em}\int\limits\os\hspace{-1.5em}\ve B\cdot\dd\ve A}
&\text{Faraday's law of induction}
\end{align}\]

Answer 3

\[\href{ http://animals.nationalgeographic.com/animals/mammals/spider-monkey }{Monkey}\]

Answer 4

\[\href{http://stack\_overflow.com/\~foo\%20bar\#link}{here}\]

Answer 5

\[\href{ http://animals.nationalgeographic.com/animals/mammals/spider-monkey \#link}{Monkey}\]

Answer 6

\[\href{ http://animals.nationalgeographic.com/animals/mammals/spider-monkey#link }{Monkey}\]