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yes; 1 : 5 yes; 1 : 2 yes; 1 : 6 no
umm the question is....?
try this: large divide by small \[{2\over6}={1\over3}\\ {7\over42}={1\over6}\\ {17\over34}={1\over2} \] since the ratios are not equal, the two figures are not geometrically scaled!
are they similar ? If they are then give them in order of least then greatest
i figured that to be the question. two geometrical figures are similar, iff their sides are in equal ratios
ok
@Noemi95 how do I figure this out ?
are we still talking about ratios and all that?
yeah
okay well I think you should figure out the volume of the shapes first
17*7*2 =238 6*42*34=8568
actually, I think the answer is no. Because just like electrokid said "two geometrical figures are similar, if their sides are in equal ratios" and the sides of this two shapes specifically are not equal in ratios.
okay . thank you . what about the one im about to post ? can you walk me through that one ?
yes; 1 : 3 yes; 1 : 2 yes; 1 : 5 no
Okay so, recall that two figures are similar, if sides are equal in ratio, so let's take a close look to the sides. length= 54 in large figure, & 18 in small one. 54/18=3 height=12 in large, & 4 in small. 12/4=3 width= 21 in large, 7 in small. 21/7=3 Notice that the sides of the figures are all proportional, therefore we CAN figure out a ratio. of 1:3
Because in every large figure, there's 3 small ones. Does it make sense?
thank you
(:
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