Question

For a right circular cylinder, if the radius is tripled and the height is shrunk down to half its size, then what is the surface area if the original radius is 7 inches and the original height is 17 inches?

Answer 1

@Mertsj

Answer 2

Can you please help me?

Answer 3

so what is the surface area originally? better yet, what's the formula?

Answer 4

Im looking

Answer 5

2 π r2 + 2 π r h

Answer 6

surface area for a right circular cylinder
\[2\pi*r*h\]
3times the "r" and half(1/2) the "h" would be
\[2\pi*3r*h(\frac{1}{2})\]
r=7, h=17
\[2\pi*3(7)*17(\frac{1}{2})\
\]

Answer 7

1120.98?

Answer 8

well, I get 1121.548

Answer 9

3892.43 both of you aren't using the total surface area. just the lateral surface area ...

Answer 10

also known as you forgot to add the circle on the top and bottom and are only using the surfacea area of the side. total surface area = ( 2*Pi*r^2 + 2*Pi*r*h)

Answer 11

right

Answer 12

hmmm, I guess I need a better formulas sheet :|