http://answers.yahoo.com/question/index?qid=20130420191834AA0bAYF Can someone please help me with domain and range for log functions?
can log(0) exist?
I think so.
use a calculator, try it out
no, its undefined look at this graph http://www.wolframalpha.com/input/?i=log%28x%29
I don't know how to, I just learned this yesterday :x
ok, well as tomo so kindly stated, log(0) does not exist
Ohhh, so it's log10 right?
now try log(1)
0?
now, try log(10), log(100), log(1000)
1,2, and 3?
remember log(x^y) = y*log(x) remember 10 = 10^1 100 = 10^2 ...
anyways, domain refers to all possible x values we know that 1 exists in the domain, but 0 does not if x goes to an ridiculously high number, then some value will still exists if x goes down to a ridiculously low number, like .0000000000000000000001, then it will also still exists, except until it reaches 0
Okay.
so what do you think the domain would be?
So x=infinite?
well remember, domain refers to a range so its from one number to another
I don't understand
domain refers to all possible x values in the function it is generally written as a range of numbers, ex. (1, 100] means from 1 to exactly 100, the parenthesis means that 1 is not included within the range the bracket means up to exactly 100 in your case, its goes from 0 to infinity but 0 is not included within the domain
So how would I determine the domain?
y=log5(2x+2)+5 ok now remember, for logn( ) where n is any number whatever is within the parenthesis cannot be 0 and can go up to infinity basically, 0 is the lower limit of the domain infinity is the upper limit of the domain so we start by looking at the expression within log5 2x+2 the lowest limit is zero, so 2x+2= 0 and we solve for x
x can't be zero.
ln(x) = y is the same exact thing as e^y = x. is there any way 2.7^? = 0
or < 0...
Wait, I don't understand.
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