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Mathematics 22 Online
OpenStudy (anonymous):

http://answers.yahoo.com/question/index?qid=20130420191834AA0bAYF Can someone please help me with domain and range for log functions?

OpenStudy (anonymous):

can log(0) exist?

OpenStudy (anonymous):

I think so.

OpenStudy (anonymous):

use a calculator, try it out

OpenStudy (anonymous):

no, its undefined look at this graph http://www.wolframalpha.com/input/?i=log%28x%29

OpenStudy (anonymous):

I don't know how to, I just learned this yesterday :x

OpenStudy (anonymous):

ok, well as tomo so kindly stated, log(0) does not exist

OpenStudy (anonymous):

Ohhh, so it's log10 right?

OpenStudy (anonymous):

now try log(1)

OpenStudy (anonymous):

0?

OpenStudy (anonymous):

now, try log(10), log(100), log(1000)

OpenStudy (anonymous):

1,2, and 3?

OpenStudy (anonymous):

remember log(x^y) = y*log(x) remember 10 = 10^1 100 = 10^2 ...

OpenStudy (anonymous):

anyways, domain refers to all possible x values we know that 1 exists in the domain, but 0 does not if x goes to an ridiculously high number, then some value will still exists if x goes down to a ridiculously low number, like .0000000000000000000001, then it will also still exists, except until it reaches 0

OpenStudy (anonymous):

Okay.

OpenStudy (anonymous):

so what do you think the domain would be?

OpenStudy (anonymous):

So x=infinite?

OpenStudy (anonymous):

well remember, domain refers to a range so its from one number to another

OpenStudy (anonymous):

I don't understand

OpenStudy (anonymous):

domain refers to all possible x values in the function it is generally written as a range of numbers, ex. (1, 100] means from 1 to exactly 100, the parenthesis means that 1 is not included within the range the bracket means up to exactly 100 in your case, its goes from 0 to infinity but 0 is not included within the domain

OpenStudy (anonymous):

So how would I determine the domain?

OpenStudy (anonymous):

y=log5(2x+2)+5 ok now remember, for logn( ) where n is any number whatever is within the parenthesis cannot be 0 and can go up to infinity basically, 0 is the lower limit of the domain infinity is the upper limit of the domain so we start by looking at the expression within log5 2x+2 the lowest limit is zero, so 2x+2= 0 and we solve for x

OpenStudy (anonymous):

x can't be zero.

OpenStudy (zzr0ck3r):

ln(x) = y is the same exact thing as e^y = x. is there any way 2.7^? = 0

OpenStudy (zzr0ck3r):

or < 0...

OpenStudy (anonymous):

Wait, I don't understand.

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