A factory has acidic wastewater to be neutralized. Analysis shows that the wastewater has a hydrogen ion concentration of 0.60 moldm-3. Calculate the mass of slaked lime, Ca(OH)2, that should be added to each dm3 of the wastewater to completely neutralize the acid.
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OpenStudy (anonymous):
@Callisto
OpenStudy (callisto):
Can you write the ionic equation?
OpenStudy (anonymous):
ahh..... is it : H+ + OH- →H2O?
O.o i don't know what have I learnt in Chemistry lesson....my teacher always absent
OpenStudy (callisto):
It should be
\[2H^{+} + Ca(OH)_2\rightarrow Ca^{2+} + H_2O\]
OpenStudy (anonymous):
ahhhh.....................
and?
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OpenStudy (callisto):
From the equation, two moles of H+ ions require one mole of Ca(OH)2 for complete neutralization. Now, for each dm^{-3}, you have 0.60 mole of H+, how many moles of Ca(OH)2 do you need for complete neutralization?
OpenStudy (anonymous):
1.2mol?
OpenStudy (callisto):
No..
OpenStudy (anonymous):
oops..
OpenStudy (anonymous):
0.3 /.\??
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OpenStudy (callisto):
Yes.
OpenStudy (callisto):
Mole = mass / molar mass
So,
mass required = no. of moles of Ca(OH)2 x molar mass of Ca(OH)2
OpenStudy (anonymous):
ah ha, let me work it out
OpenStudy (anonymous):
22.23g?
OpenStudy (callisto):
Yes.
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