Question

Help

Answer 1

why don't we take it step by step, even though there might be a snappier way to do it

Answer 2

Sure =)

Answer 3

you want
\[(A\cup B)'\cap B\] so first lets find \(A\cup B\) and then we can find \(A\cup B)'

Answer 4

Sure got it.

Answer 5

that is we can find \((A\cup B)'\)

Answer 6

so \(A\cup B\) is everything in A or in B or both
what do you get for that?

Answer 7

? huh

Answer 8

i am asking if you know what \(A\cup B\) is in this case
make a list of all things in A and also all things that are in B

Answer 9

1,2,3,...10

Answer 10

Which set is 7 in? A or B?

Answer 11

there are a couple more
make a complete list

Answer 12

okay good
now delete the ones you have written twice

Answer 13

good?

Answer 14

yes but you don't need to list an element twice, only once

Answer 15

put back the list you had

Answer 16

1,2,3,4,5,10
2,3,4,6

Answer 17

ok now lets rewrite it as one list, with no elements repeated
\[\{1,2,3,4,5,6,10\}\]

Answer 18

Ok

Answer 19

got that part? that is \(A\cup B\)

Answer 20

Yes

Answer 21

okay good
now we find \((A\cup B)'\) which means everything in \(U\) that is NOT in \(A\cup B\)
so take a look at \(U\) and pick out everything that is in \(U\) that is not in \(A\cup B\)

Answer 22

1

Answer 23

10

Answer 24

okay i think i see where the confusion is
the lazy grad student who wrote this question did not feel it worth their while to write out what \(U\) is exactly
the first line of the question should have
\[U=\{1,2,3,4,5,6,7,8,9,10\}\]

Answer 25

7

Answer 26

so your job is to pick out everything in \[U=\{1,2,3,4,5,6,7,8,9,10\}\] that is not in \[\{1,2,3,4,5,6,10\}\]

Answer 27

yeah one of those will be \(7\) that is right, but there are a couple others

Answer 28

thats 7 8 9

Answer 29

that is the list, yes

Answer 30

It said find the set that is in parenthesis

Answer 31

so now we have
\[(A\cup B)'=\{7,8,9\}\]

Answer 32

Yup

Answer 33

your final job is to find \[(A\cup B)'\cap B\]

Answer 34

Can you tell me real quick ,I am getting timed out.

Answer 35

that is everything that is in BOTH
okay sure, it is empty

Answer 36

I don't want to fail

Answer 37

no failing is not fun
but there is nothing that is in B and also not in B at the same time, so your answer is the empty set, which they want you to write as N

Answer 38

So just write N

Answer 39

yes

Answer 40

you might could have seen this right away, since \((A\cup B)'=A'\cap B'\) and
\[A\cap B'\cap B\] is empty since there cannot be anything that is both in \(B\) and not in \(B\)