Question

Find the standard form of the equation of the parabola with a focus at (–4, 0) and a directrix at x = 4

Answer 1

@ChipperJay*

Answer 2

That means the vertex is the midpoint of the directrix and the focus which means that it is (0,0), so that and the formula is y=(1/4n)x^2 and n is 4 because that is the distance from the directrix to the vertex. So the equation is y=(1/16)x^2.

Answer 3

thank you so much

Answer 4

@rrrrr

Answer 5

what about this one

Answer 6

A building has an entry the shape of a parabolic arch 96 ft high and 18 ft wide at the base as shown below.

Answer 7

Find an equation for the parabola if the vertex is put at the origin of the coordinate system.

Answer 8

my answer was y = (-32/27)(x - 0)^2 + 0

Answer 9

is this correct?

Answer 10

I'm not sure for this one, you should ask someone else :( sorry

Answer 11

oh :( alright
thanks anyway!

Answer 12

could I ask you another question similar to the first? :)

Answer 13

kk

Answer 14

just wanna make sure I've got the right answers and my work is correct :)

Answer 15

I don't know this question. I apologize for this, but thanks for mentioning me anyway. I feel special. :)

Answer 16

sure :D

Answer 17

Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, 9). and I got: y=1/36x^2

Answer 18

aw, it's alright. thanks anyway @ChipperJay* :)

Answer 19

yes because 1/4n and n=9 so 1/36
so that is correct

Answer 20

yes! thanks so much. :)

Answer 21

youre welcome

Answer 22

sorry could I ask you just oneeee more final question?

Answer 23

Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8

Answer 24

@doppler @rrrrr @ChipperJay* :)

Answer 25

ok that will be y=(1/32)x^2
using the formula I mentioned

Answer 26

alright thanks :)