Question

Apply the convolution theorem to find the inverse Laplace transform of the function:
F(s) = s^2/(s^2+ 4)^2

Answer 1

remind me what the convolution theorem (sounds convoluted)

Answer 2

Laplace{f*g} = Laplace {f(t)}Laplace{g(t)} = F(s)G(s)

Answer 3

s^2/(s^2+4) * (2/2)1/(s^2+4)

Answer 4

is it familiar?

Answer 5

from the original equation, I get \[s/(s^2+4) * s/(s^2+4)\]

Answer 6

you have the tables?

Answer 7

yes, both equations refer to cos equations

Answer 8

ah you can do it that way too yes

Answer 9

do you have a final answer? I think I may have one

Answer 10

you are correct i think

Answer 11

\[\int\limits_{0}^{t}\cos4xcos4(x-t)dx\] and so on

Answer 12

sorry 2 there instead of 4

Answer 13

yep I have that!