Question

Find the following integrals:

Answer 1

?

Answer 2

What integrals?

Answer 3

\[\int\limits_{}^{} 3x^2+5x^4 / x^5+x^3\]

Answer 4

i have to use the equation thing to put them in bcuz its easier

Answer 5

Do you mean \(\dfrac{3x^{2} + 5x^{4}}{x^{5} + x^{3}}\)? That is NOT what you have written.

Try u = (the entire denominator).

Answer 6

thats how it should be written i didnt know how to get it like that

Answer 7

Use parentheses. (3x^2 + 5x^4)/(x^5 + x^3)

Answer 8

i also left off the dx at the end.....sorry

Answer 9

thanks for the tip @tkhunny

Answer 10

Don't worry about the "dx". It's more important when the context is unclear.

Answer 11

\[\int\limits_{}^{} 2xe^3x^2 dx\]

Answer 12

for this one the the e should hav 3x^2 in the air

Answer 13

\[\int\limits_{}^{}3x^2+5x^4/x^5+x^3\]
take x^2 common from both dnr. and Numr. and u'll get\[\int\limits_{}^{}(3+5x^2/x^3+x)dx\] now split from the plus sign and u'll get 2 intregals one can be solved by partial fraction by taking x common from dnr. and other by simple substitution of Dnr.

Answer 14

1) Do NOT simplify the fraction before doing the substitution I suggested. \(u = x^{5} + x^{3}\). It's in a perfectly fine form as it is.

2) Don't use bad notation. Remember your Order of Operations and add parentheses for clarity.

Answer 15

If you add braces around your exponent, it will all move up.

e ^ 3 x ^ 2 results in \(e^3x^2\)

e ^ { 3 x ^ 2 } results in \(e^{3x^2}\)

Use \(u = 3x^{2}\)