prove that if p<= n, then p does not divide n!+1 Please help
this is the proof to the prime numbers being infinite
Is that your question ,|dw:1366612494386:dw|
more like... \[\huge p < n \ \ \rightarrow \ \ \frac{n! + 1}{p}\notin \mathbb{Z}\]
Okay... no need to get so edgy :D\[\huge p \le n \ \ \rightarrow \ \ \frac{n! + 1}{p}\notin \mathbb{Z}\]
1 is not a prime
oh... lol I didn't know p had to be a prime :) I just took it for a variable. My bad :D
Why does p even have to be prime? Doesn't it apply for all integers greater than 1?
yes i understand the question, but i have no idea how to start this question.. D:
Familiar with modular math, @neoc? :)
@terenzreignz yes iam familiar with modular math
That is awesome :) Then you'd know that if 1 < p < n then \[\huge p\lvert n!\] right? Because \[\huge n! = n\cdot(n-1)\cdot...p ...3\cdot2\cdot1\]or something
oh yes! thank you so much! it all make sense now :D
Wow.. that escalated quickly :D No problem :)
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