Phase shift help plz.

Question

anonymous · Answer

$$y=4\sin \left( 4\pi x-3 \right)$$

amistre64 · Answer

your question is vague

amistre64 · Answer

factor out the 4pi, and whats left adding to the x is the horizontal (or phase) shift

amistre64 · Answer

and by adding, i mean subtracting from of course :)

anonymous · Answer

\[-\frac{ 3 }{ 4pi] is the answer

amistre64 · Answer

almost, the negative is wrong

amistre64 · Answer

$$(x-p)$$
p = phase

anonymous · Answer

does that mean its 3/4pi

amistre64 · Answer

yes, $$(x-\frac3{4pi})~:~phase=\frac3{4pi} $$

anonymous · Answer

so i subract when i  was post to add

anonymous · Answer

thank u

amistre64 · Answer

the visual does seem backwards, but it proper for the mathing.  a "shift" means that we are moving all the points of a curve to equivalent curve that goes thru the origin.

spose you had the point (10,4) on some family of the x^2 function; we know that 10^2 does not equal 4, by moving all the points by -10 on the xs and +4 on the ys we can get:

(y+4) = (x-10)^2  as the "shifted" equivalent.

the "shift" shows up in the equation as:  -10, because the actual equation is at +10

if that makes any sense :)