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OpenStudy (anonymous):

please help. photo attcahed. i have no idea what i have to do.

OpenStudy (anonymous):

OpenStudy (anonymous):

make a u substitution

OpenStudy (anonymous):

backwards

OpenStudy (anonymous):

the questions are seems different from substitution questions :/

OpenStudy (anonymous):

that is because the substitution is backwards

OpenStudy (anonymous):

could you show me the steps for A so i may do questions B and C for myself?

OpenStudy (anonymous):

yeah i am trying to think of a good way to write it, hold on a second

OpenStudy (anonymous):

thank you,

OpenStudy (anonymous):

damn let me start again the point is, we want to convert the inside piece to \(t\)

hartnn (hartnn):

we can do this, put u= 2t then use the property that definite integral remain same with variable change, 'change of variable' property.

OpenStudy (anonymous):

think of it as \[\int f(g(x))dx\] we want \[\int f(x)\] so we have to find \(g^{-1}(x)\) to convert back in the case \(f(1-4t)\) if you set \(x=1-4t\) you get \(t=\frac{1-x}{4}\)

OpenStudy (anonymous):

that is the substitution you want to make

OpenStudy (anonymous):

@hartnn i think you have to go the other way, put \(u=\frac{t}{2}\)

hartnn (hartnn):

hmmm...i was saying this : \(\int \limits_0^{0.5}f(2t) dt= \int \limits_0^{0.5}f(2u) du \\put \quad 2u=t, \\ =(1/2)\int \limits_0^1f(t)dt \) so, in 2nd case , you can do 1-4u =t

hartnn (hartnn):

no need for inverse function stuff...i think 1-4u = t -4du = dt du = dt/(-4) .....this is same thing you will get after finding inverse function ...

OpenStudy (anonymous):

i am confused...

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