This is a question that I do not have the answer to can someone check this out and tell me if I have the correct answer
The answer I got was pi(x^2+6x+9)-(2x^2+12x+18) Im, not sure if it can be factored any further
See area of triangle will be: \[\frac{1}{2} \times (2x + 6) \times (x+3) \implies x^2 + 9 + 6x\]
Circle area: \[\pi r^2 = \pi (x^2 + 9 + 6x)\] Just subtract them..
Simply tell me what did you get for Area Of Triangle and how??
There @waheguru ??
Im so sorry, I had to leave
To get the area i tried to subtract the two areas given and got pi(x^2+6x+9)-(2x^2+12x+18)
Okay..
But, Im not exacly sure what to do next
But now I have to go.. See, just find the area of triangle, Base = 2x + 6 and Height = x + 3.. You are getting wrong area for triangle..
See, 2x + 6 is the diameter as well as base, half of it will be Height of triangle as well as Radius.. So Area of triangle will be: \[\frac{1}{2} \times (2x+6) \times (x+3) = Right??\]
yea
Ooh
I forgot to divide by 2
thanks
Im really sorry, but i have to leave thanks alot for your amazing help
You are welcome dear..
The area of the triangle is x^2+6x+9 and the area of the circle is pi( x^2+6x+9) how do I simplyify this to find the area of the shaded region (question in attachment at top)
(x+3)^2(pi - 1)
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