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Mathematics 18 Online
OpenStudy (waheguru):

This is a question that I do not have the answer to can someone check this out and tell me if I have the correct answer

OpenStudy (waheguru):

OpenStudy (waheguru):

The answer I got was pi(x^2+6x+9)-(2x^2+12x+18) Im, not sure if it can be factored any further

OpenStudy (anonymous):

See area of triangle will be: \[\frac{1}{2} \times (2x + 6) \times (x+3) \implies x^2 + 9 + 6x\]

OpenStudy (anonymous):

Circle area: \[\pi r^2 = \pi (x^2 + 9 + 6x)\] Just subtract them..

OpenStudy (anonymous):

Simply tell me what did you get for Area Of Triangle and how??

OpenStudy (anonymous):

There @waheguru ??

OpenStudy (waheguru):

Im so sorry, I had to leave

OpenStudy (waheguru):

To get the area i tried to subtract the two areas given and got pi(x^2+6x+9)-(2x^2+12x+18)

OpenStudy (anonymous):

Okay..

OpenStudy (waheguru):

But, Im not exacly sure what to do next

OpenStudy (anonymous):

But now I have to go.. See, just find the area of triangle, Base = 2x + 6 and Height = x + 3.. You are getting wrong area for triangle..

OpenStudy (anonymous):

See, 2x + 6 is the diameter as well as base, half of it will be Height of triangle as well as Radius.. So Area of triangle will be: \[\frac{1}{2} \times (2x+6) \times (x+3) = Right??\]

OpenStudy (waheguru):

yea

OpenStudy (waheguru):

Ooh

OpenStudy (waheguru):

I forgot to divide by 2

OpenStudy (waheguru):

thanks

OpenStudy (waheguru):

Im really sorry, but i have to leave thanks alot for your amazing help

OpenStudy (anonymous):

You are welcome dear..

OpenStudy (waheguru):

The area of the triangle is x^2+6x+9 and the area of the circle is pi( x^2+6x+9) how do I simplyify this to find the area of the shaded region (question in attachment at top)

OpenStudy (mertsj):

(x+3)^2(pi - 1)

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