Question

I'm assuming it's still the case, but say you have a function with two terms involving x; if one ends up undefined (div. by zero e.g.), but the other doesn't, the function's output is still considered undefined as a whole for that input, right?

Answer 1

a halo fan eh?

i guess you mean:
\[f(x) = g(x) + h(x)\]
where g(x) is undefined, but h(x) is?

then yeah, you're right.

Answer 2

Yeah. Thanks! And, yes, lol.