solve 2sin^2x=1 over domain of -4pi (greater than or equal to) x (greater than or equal to) -3pi

give exact answers.. i am a visual learner.. if u can draw out the pi chart that would be great.. domain always messes me thanks

Question

solve 2sin^2x=1 over domain of -4pi (greater than or equal to) x (greater than or equal to) -3pi


give exact answers.. i am a visual learner.. if u can draw out the pi chart that would be great.. domain always messes me thanks

anonymous · Answer

$$2\sin^2x=1\
\sin^2x={1\over2}\
\implies \sin x=\pm{1\over\sqrt{2}}$$
now you can get the "x"