Question

Please help me solve this its all factoring.
medal will be given thanks.

1. 2y^2-3^z
2. 4x^2-y^2+2y-1
3. 16p^2-(5q-r)^2
4. 4x^3+40x^2+100x
5. m^6-n^6

Answer 1

Q2.
(2x - y - 1) (2x + y - 1)

Answer 2

Q1.
I dont think you can factor this any further...

Answer 3

thanks jack can you put the solution also it would help me a lot so i can review it.

Answer 4

For question 4.
\[4x^3+40x^2+100x\]

you can factor out \(4x\) from each term

Answer 5

y = ax^2 + by^2 + cy + d
so
4x^2-y^2+2y-1
= 4x^2 - (y-1)^2
= (2x - y - 1) (2x + y - 1)

Answer 6

thank you UnkleRhaukus i will try to solve it and Jack1 appreciated.

Answer 7

Q3
16p^2-(5q-r)^2
the 16p^2 = 4p x 4p
and the (5q-r) ^2 = (5q-r) (5q+r)
so
= (4p +5q - r) (4p -5q + r)

Answer 8

Q5... I'm out...? sorry
i know it will be a large combination of (m - n) (m + n)...?

Answer 9

for 5. \[m^6-n^6\]

it helps to temporarily set \[m^3=M, \qquad n^3=N\]

Answer 10

so factorise \(M^2-N^2\) = ...

Answer 11

for 1. im not sure if you typed it correctly?

Answer 12

thanks you unklerhaukus 1. is written mistakely its 2y^2-3z im sorry for that.

Answer 13

hmm, well 1. still can not be factored.

Answer 14

thanks you unkle im currently answering the other no ill post later with the answers