If the price charged for a candy bar is p(x) cents, then x thousands candy bars will be sold in a certain city, where p(x)=101-x/24. How many candy bars must be sold to maximize revenue?

Question

anonymous · Answer

classic. substitute the p(x) function into first equation. then optimize -- Derive and find a zero. Plug that x coordinate of the zero into the second derivative. if you get a positive number then that is the max revenue.