Question

PROVING IDENTITIES!!!

Answer 1

qn

Answer 2

\[\frac{ 1 + \sin x }{ 1 - \sin x } - \frac{ 1 - \sin x }{ 1 + \sin x } = 4 \tan x \sec x\]

Answer 3

\[\frac{ (1+\sin x)^2 + (1-\sin x)^2 }{ (1+\sin x) (1-\sin x) }\]

Answer 4

sorry that was minus; oops. :P

i'll correct it.

\[\frac{ 1 + 2\sin x + \sin^2x - (1 - 2\sin x + \sin^2x) }{ 1 - \sin^2x }\]

Answer 5

On simplifying -

\[\frac{ 4\sin x }{ \cos^2x } => \frac{ 4 \sin x }{ \cos x } . \frac{ 1 }{ \cos x }\]

Answer 6

I hope you can do it from here -

Answer 7

thank you!...i can continue from there